Problem:
Simplify $ \frac{7}{56} $
Solution:
$ \frac{1}{8} $
Monday, August 31, 2015
$ \frac{2x^2}{7} \times \frac{3}{4x^2} $
Problem:
$ \frac{2x^2}{7} \times \frac{3}{4x^2} $
Solution:
$ \frac{3}{14} $
$ \frac{2x^2}{7} \times \frac{3}{4x^2} $
Solution:
$ \frac{3}{14} $
0 = b squared - 4 a c = 3^2 - 4(1)-3
Problem:
The problem is only this equation
0 = b squared - 4 a c = 3^2 - 4(1)-3
Solution:
This is incorrect, first or all, if you multiply a negative number, you cannot just write the number at the end like -3, this is minus 3, not multiply negative 3, you need to add a bracket there.
Alright, assume the bracket is there, the equation is still not right, 3^2 - 4(1)(-3) = 21 is not zero.
Alright, ignoring the 0 part, it means we have B = 3, A = 1, C = -3, then the answer is given by
$ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-3 \pm \sqrt{21}}{2} $.
The problem is only this equation
0 = b squared - 4 a c = 3^2 - 4(1)-3
Solution:
This is incorrect, first or all, if you multiply a negative number, you cannot just write the number at the end like -3, this is minus 3, not multiply negative 3, you need to add a bracket there.
Alright, assume the bracket is there, the equation is still not right, 3^2 - 4(1)(-3) = 21 is not zero.
Alright, ignoring the 0 part, it means we have B = 3, A = 1, C = -3, then the answer is given by
$ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-3 \pm \sqrt{21}}{2} $.
Ordering numbers
Problem:
Order the numbers:
$ \sqrt{8}, -3.75, 3, \frac{9}{4} $
Solution:
$ -3.75 < \frac{9}{4} < \sqrt{8} < 3 $
Order the numbers:
$ \sqrt{8}, -3.75, 3, \frac{9}{4} $
Solution:
$ -3.75 < \frac{9}{4} < \sqrt{8} < 3 $
Rectangle
Problem:
The length of the rectangle is 4 times it width, the rectangle's width is 8m.
What is the area of the rectangle..
Solution:
Length = 32 meter, Area = 256 meter squared
The length of the rectangle is 4 times it width, the rectangle's width is 8m.
What is the area of the rectangle..
Solution:
Length = 32 meter, Area = 256 meter squared
Simplify
Problem:
$ \frac{x^{-1/3}y^{-3/4}x^{-7/4}}{(y^{-2/3})^{4/3}} $
Answer:
$ \frac{y^{5/36}}{x^{25/12}} $
$ \frac{x^{-1/3}y^{-3/4}x^{-7/4}}{(y^{-2/3})^{4/3}} $
Answer:
$ \frac{y^{5/36}}{x^{25/12}} $
6(2x-6)=-3(-4x-3)-5
Problem:
6(2x-6)=-3(-4x-3)-5
Solution:
There is something wrong with the problem, it simplifies to
12x - 36 = 12x + 4
There is no x that can make this equation true, in another words, the answer is no solution.
6(2x-6)=-3(-4x-3)-5
Solution:
There is something wrong with the problem, it simplifies to
12x - 36 = 12x + 4
There is no x that can make this equation true, in another words, the answer is no solution.
Opposites
To move three units from -7, we can do it either to the left or to the right
Let start with moving to the right, we start at -7
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
Then we move the other way, we get
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
So the answer is -4 and -10
Let start with moving to the right, we start at -7
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
Then we move the other way, we get
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0
*
So the answer is -4 and -10
Graphing f(x)/2
Problem:
Graphing, $ y = \frac{1}{2}f(x) $
Solution:
Without a specific $ f(x) $ given, I just used a random $ f(x) = (x - 2)(x - 4)(x - 6) $.
Here is a graph with both $ f(x) $ and $ \frac{1}{2}f(x) $.
Graphing, $ y = \frac{1}{2}f(x) $
Solution:
Without a specific $ f(x) $ given, I just used a random $ f(x) = (x - 2)(x - 4)(x - 6) $.
Here is a graph with both $ f(x) $ and $ \frac{1}{2}f(x) $.
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