0 = b squared - 4 a c = 3^2 - 4(1)-3

Problem:

The problem is only this equation

0 = b squared - 4 a c = 3^2 - 4(1)-3

Solution:

This is incorrect, first or all, if you multiply a negative number, you cannot just write the number at the end like -3, this is minus 3, not multiply negative 3, you need to add a bracket there.

Alright, assume the bracket is there, the equation is still not right, 3^2 - 4(1)(-3) = 21 is not zero.

Alright, ignoring the 0 part, it means we have B = 3, A = 1, C = -3, then the answer is given by

$ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-3 \pm \sqrt{21}}{2} $.